(1)/(16^(2x+1))=16

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Solution for (1)/(16^(2x+1))=16 equation: 



(1)/(16^(2x+1))=16

We move all terms to the left:

(1)/(16^(2x+1))-(16)=0



Domain of the equation: (16^(2x+1))!=0

x∈R



We multiply all the terms by the denominator


-16*(16^(2x+1))+1=0

We move all terms containing x to the left, all other terms to the right

-16*(16^(2x+1))=-1

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